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(Solved): Trial 1 Trial 2 Trial 3 Mass (volume) Of Cold Water 65.0 Ml 65.0 Ml 65.0 Ml Temperature Of Cold Wat...
Trial 1 |
Trial 2 |
Trial 3 |
|
Mass (volume) of cold water |
65.0 ml |
65.0 ml |
65.0 ml |
Temperature of cold water |
21.3°C |
23.3°C |
23.3°C |
Mass (volume) of hot water |
65 ml |
65 ml |
65 ml |
Temperature of hot water |
55.6°C |
61.9°C |
62.0°C |
Final temperature reached |
34.4°C |
39.0°C |
38.5°C |
Temperature change, ΔT |
°C |
°C |
°C |
Calorimeter constant |
J/g×°C |
J/g×°C |
J/g×°C |
Mean Value of Calorimeter Constant: J/ g×°C |
Calculate the Temperature change, the Calorimeter constant, and Mean value. Please show your work.
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Expert Answer
The temperature change is calculated in each case: T = Tf - Ti = 34.4 - 21.3 = 13.1 C Trial 2: 15.7 C Trial 3: 15.5 C The heat transferred
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