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(Solved): Trial 1 Trial 2 Trial 3 Mass (volume) Of Cold Water 65.0 Ml 65.0 Ml 65.0 Ml Temperature Of Cold Wat...


Trial 1

Trial 2

Trial 3

Mass (volume) of cold water

65.0 ml

65.0 ml

65.0 ml

Temperature of cold water

21.3°C

23.3°C

23.3°C

Mass (volume) of hot water

65 ml

65 ml

65 ml

Temperature of hot water

55.6°C

61.9°C

62.0°C

Final temperature reached

34.4°C

39.0°C

38.5°C

Temperature change, ΔT

°C

   °C

   °C

Calorimeter constant

   J/g×°C

J/g×°C

J/g×°C

Mean Value of Calorimeter Constant: J/ g×°C

Calculate the Temperature change, the Calorimeter constant, and Mean value. Please show your work.



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Expert Answer


The temperature change is calculated in each case: T = Tf - Ti = 34.4 - 21.3 = 13.1 C Trial 2: 15.7 C Trial 3: 15.5 C The heat transferred
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