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(Solved): The Acceleration Of A Particle Moving Only On A Horizontal Xy Plane Is Given By á = 3ti + 4tj, Wher...


The acceleration of a particle moving only on a horizontal xy plane is given by á = 3ti + 4tj, where á is in meters per secon

The acceleration of a particle moving only on a horizontal xy plane is given by á = 3ti + 4tj, where á is in meters per second-squared and t is in seconds. At t = 0, the position vector ř = (26.0m)i + (41.0m)j locates the paticle, which then has the velocity vector V = (4.20m/s)i + (3.50m/s)j. At t = 6.00 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis? (a) Number i Î Units (b) Number So Units


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