(Solved): PLEASE SHOW THE WORK ON HOW TO GET THE ANSWER PLEASE A Company Has An IP As 220.127.116.11/27 Which Cl...
PLEASE SHOW THE WORK ON HOW TO GET THE ANSWER PLEASE
A company has an IP as 18.104.22.168/27
Whatâ€™re the NetID, hostID and network address (if without subnet)?
199.21.12 40 22.214.171.124
Whatâ€™s the default mask?
How many bits for subnet?
A = B +C
B is the bit number of NetId
C is the bit number of Subnet
A= 27, B = 3 bytes = 3x8 =24 bits
So, we get C= 3
3 bits for subnet
How many bits left for hostID?
Before HostID has 1 byte = 8bits
Now hostID has 8-3 = 5 bits
Whatâ€™s the submask?
Default mask: 255.255.255.0
Convert it into bits: 255.255.255.00000000
3 bits taken from hostID for subnet: 255.255.255.00000000
Change the three 0s to 1s: 255.255.255.11100000
Convert it into decimal: 255.255.255.224
The submask is 255.255.255.224
How many subnets does it provide?
2n , n is the bits borrowed from hostid for subnet
Here n = 3
So, we have 23 = 8
How many host IP in each subnet?
2m-2, here m is the bit number left for hostID. m= 5
So, 25-2 = 32 -2 =30
Pick any subnet, then list the bits for that subnet chosen, give the subnet address, IP range and broadcast IP for that subnet.
Network address 126.96.36.199
3 bits for subnet: 199.21.12. 00000000
I choose the 3 bits as 001 for the subnet
199.21.12.00100000 -Ã subnet address: 188.8.131.52
199.21.12.00100001 -Ã 1st host IP address: 184.108.40.206
199.21.12.00100010 -Ã 2nd host IP address: 220.127.116.11
199.21.12.00111110 -Ã last host IP address: 18.104.22.168
199.21.12.00111111 -Ã Broadcast IP address for this subnet: 22.214.171.124